Mathfolis

Logarithmic Expressions

Unit 2 · Exponential and Logarithmic Functions

What AP Precalc asks here

A logarithm answers the question: what power of the base bb gives xx? Symbolically, logbx=y\log_b x = y iff by=xb^y = x. The common log is base 10, the natural log is base ee. The argument xx must be positive — logbx\log_b x is undefined for x0x \leq 0 (and the base must satisfy b>0,b1b > 0, b \neq 1).

Definition

Equivalence
logbx=y    by=x(b>0,b1,x>0)\log_b x = y \iff b^y = x \quad (b > 0, b \neq 1, x > 0)

Special values

logb1\log_b 1
=0= 0
logbb\log_b b
=1= 1
logb(bk)\log_b(b^k)
=k= k
Inverse identity
blogbx=xb^{\log_b x} = x
Caution: Logarithms of zero or negative numbers are undefined. Always check the argument is positive before evaluating.
Type 1

Direct evaluation

Rewrite the argument as an integer power of the base, then read off the exponent.

Example 1
Evaluate log232\log_2 32. (A) 44 (B) 55 (C) 66 (D) 3232

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Type 2

Convert exponential to logarithmic form

Rewrite by=xb^y = x as y=logbxy = \log_b x, isolating the exponent on the right.

Example 2
Rewrite 3x=73^x = 7 in logarithmic form. (A) x=log73x = \log_7 3 (B) x=log37x = \log_3 7 (C) 7=logx37 = \log_x 3 (D) x=7log3x = 7 \log 3

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Type 3

Domain and special-case identities

Apply logb1=0\log_b 1 = 0, logbb=1\log_b b = 1, logb(bk)=k\log_b(b^k) = k. Reject negative arguments as undefined.

Example 3
Which of the following is undefined? (A) log232\log_2 32 (B) log3(1/27)\log_3(1/27) (C) log2(8)\log_2(-8) (D) ln(e4)\ln(e^4)

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Logarithmic Expressions | AP Precalculus — Mathfolis