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Exponential and Logarithmic Equations and Inequalities

Unit 2 · Exponential and Logarithmic Functions

What AP Precalc asks here

Exponential equations are usually solved by rewriting both sides to a common base (then equating exponents) or by taking a log of both sides. Log equations are solved by exponentiating to remove the log, but every candidate must be checked: a value that makes any log argument non-positive is extraneous. Some mixed equations like b2xcbx+d=0b^{2x} - cb^x + d = 0 yield to the substitution u=bxu = b^x.

Solving strategies

Same base
bA=bB    A=Bb^A = b^B \;\Rightarrow\; A = B
Log of both sides
bexpr=c    expr=logbcb^{\text{expr}} = c \;\Rightarrow\; \text{expr} = \log_b c
Exponentiate
logb(expr)=c    expr=bc\log_b(\text{expr}) = c \;\Rightarrow\; \text{expr} = b^c
Caution: Every log equation requires an extraneous-root check. After solving algebraically, verify each candidate makes every log argument strictly positive.
Type 1

Solve an exponential equation

Rewrite both sides to a common base if possible; otherwise take a log of both sides.

Example 1
Solve 2x=322^x = 32. (A) x=4x = 4 (B) x=5x = 5 (C) x=16x = 16 (D) x=30x = 30

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Type 2

Solve a log equation (check extraneous)

Combine logs, exponentiate, solve the resulting polynomial, then verify each candidate makes the original log arguments positive.

Example 2
Solve logx+log(x3)=1\log x + \log(x - 3) = 1. (A) x=2x = -2 (B) x=5x = 5 (C) x=2x = -2 and x=5x = 5 (D) No solution

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Type 3

Substitution and inequalities

Substitute u=bxu = b^x in mixed exponential equations. For inequalities, isolate, exponentiate, and preserve direction when b>1b > 1.

Example 3
Solve 4x52x+4=04^x - 5 \cdot 2^x + 4 = 0. (A) x=0x = 0 only (B) x=2x = 2 only (C) x=0x = 0 and x=2x = 2 (D) No real solutions

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Exponential and Logarithmic Equations and Inequalities | AP Precalculus — Mathfolis