Mathfolis

Circles

Unit 4 · Geometry & Trigonometry

What the SAT asks here

Circle problems on the SAT focus on three skills: writing the equation from a center and radius, converting the general form to standard form by completing the square, and computing arc length or sector area as a fraction of the whole circle. About one problem per test.

Equation of a circle

Center (h, k), radius r
(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2
General form (convert via completing the square)
x2+y2+Dx+Ey+F=0x^2 + y^2 + Dx + Ey + F = 0

Arc and sector (central angle θ in degrees)

Circumference / area
C=2πr,    A=πr2C = 2\pi r, \;\; A = \pi r^2
Arc length
s=θ3602πrs = \frac{\theta}{360^\circ} \cdot 2\pi r
Sector area
Asec=θ360πr2A_{\text{sec}} = \frac{\theta}{360^\circ} \cdot \pi r^2
SAT Tip: Arc length and sector area both scale as θ/360° of the full circle. Memorise the fraction, not the formulas — the fraction works in radians too with θ/(2π).
Caution: In (x − h)² + (y − k)² = r², the centre uses the OPPOSITE signs of what appears inside the parentheses. (x + 3)² + (y − 2)² = 25 has centre (−3, 2).
Type 1

Equation from center and radius

Plug (h, k) and r into the standard form. Be careful with signs when h or k is negative.

Example 1
Write the equation of a circle with center (2, −5) and radius 4.

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Type 2

Convert general form → standard form

Group the x-terms and y-terms separately, complete the square in each, then move the constants to the right-hand side.

Example 2
Find the center and radius of the circle x² + y² − 6x + 4y − 12 = 0.

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Type 3

Arc length or sector area

Multiply the full circumference or area by the fraction θ/360°.

Example 3
A circle has radius 6. Find the area of a sector with central angle 60°, in terms of π.

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