Mathfolis

Inverse Trigonometric Functions

Unit 3 · Trigonometric and Polar Functions

What AP Precalc asks here

Inverse trig functions reverse sin, cos, tan — but only on restricted domains, since the originals are not one-to-one. The principal ranges are: arcsin:[π/2,π/2]\arcsin: [-\pi/2, \pi/2], arccos:[0,π]\arccos: [0, \pi], arctan:(π/2,π/2)\arctan: (-\pi/2, \pi/2). Compositions like sin(arcsinx)\sin(\arcsin x) always simplify to xx within the domain, but the reverse arcsin(sinθ)=θ\arcsin(\sin\theta) = \theta only when θ\theta is in the principal range.

Principal ranges

arcsin
[1,1][π/2,π/2][-1, 1] \to [-\pi/2, \pi/2]
arccos
[1,1][0,π][-1, 1] \to [0, \pi]
arctan
R(π/2,π/2)\mathbb{R} \to (-\pi/2, \pi/2)
Caution: arcsin(sinθ)\arcsin(\sin\theta) does NOT always equal θ\theta. If θ=2π/3\theta = 2\pi/3, then sinθ=3/2\sin\theta = \sqrt 3/2, and arcsin(3/2)=π/32π/3\arcsin(\sqrt 3/2) = \pi/3 \neq 2\pi/3.
Type 1

Evaluate arcsin, arccos, arctan

Recall the special-angle value whose sin (or cos, tan) matches the input, picking the one in the principal range.

Example 1
What is arctan(1)\arctan(1)? (A) π/6\pi/6 (B) π/4\pi/4 (C) π/3\pi/3 (D) π/2\pi/2

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Type 2

Domain and range

arcsin and arccos accept inputs in [1,1][-1, 1]; arctan accepts all reals. Their outputs lie in the principal ranges.

Example 2
What is the range of arccos\arccos? (A) [π/2,π/2][-\pi/2, \pi/2] (B) [0,π][0, \pi] (C) (π/2,π/2)(-\pi/2, \pi/2) (D) [π,π][-\pi, \pi]

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Type 3

Composition with original trig

When evaluating sin(arccos x) or cos(arcsin x), use a right triangle (or the Pythagorean identity) to find the missing side.

Example 3
Evaluate cos(arcsin(3/5))\cos(\arcsin(3/5)). (A) 3/53/5 (B) 4/54/5 (C) 5/35/3 (D) 5/45/4

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